Answer to Question #313364 in Algebra for Tan

Question

for h(x) = 2/3 x -5 find the value of x for which h(x) = -7

Answer 1

Solution

Given that

$h\left( x \right) = \frac{2}{3}x - 5\$

Now for $h\left( x \right) = - 7\$

We have

$\begin{gathered} h\left( x \right) = \frac{2}{3}x - 5 \\ \Rightarrow & - 7 = \frac{2}{3}x - 5 \\ \Rightarrow & - 7 \times 3 = \frac{2}{3}x \times 3 - 5 \times 3 \\ \Rightarrow & - 21 = 2x - 15 \\ \Rightarrow & - 21 + 15 = 2x \\ \Rightarrow & - 6 = 2x \\ \Rightarrow & x = - 3 \\ \end{gathered} \$

Hence the value of $x$ for which $h(x)=-7$ is $x=-3$

We can write it as

$h(-3)=-7$