1) Without fully expanding (4a-b)7, determine the fifth term.
2) Find the middle term of (2c - 12đ)10
"1:\\\\\\left( 4a-b \\right) ^7\\\\The\\,\\,fifth\\,\\,term\\,\\,\\left( counting\\,\\,from\\,\\,0th\\,\\,term \\right) \\,\\,is\\,\\,\\\\C_{7}^{5}\\left( 4a \\right) ^5\\left( -b \\right) ^{7-5}=21504a^5b^2\\\\2:\\\\\\left( 2c-12d \\right) ^{10}\\\\The\\,\\,middle\\,\\,term\\,\\,is\\,\\,for\\,\\,5th\\,\\,powers:\\\\C_{10}^{5}\\left( 2c \\right) ^5\\left( -12d \\right) ^5=-2006581248c^5d^5"
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