Answer to Question #326569 in Algebra for bbbbbbedddds

Question

Multiply out (3x³ + 4x - 5)(2x³ - 8x² + 2) using polynomial long multiplication.

Answer 1

$(3x^3+4x-5)(2x^3-8x^2+2)=\\= 3x^3\cdot2x^3+3x^3\cdot(-8x^2)+3x^3\cdot2+\\ +4x\cdot2x^3+4x\cdot(-8x^2)+4x\cdot2-\\ -5\cdot2x^3-5\cdot(-8x^2)-5\cdot2=\\ =6x^6-24x^5+6x^3+\\ +8x^4-32x^3+8x-\\ -10x^3+40x^2-10=\\ =6x^6-24x^5+8x^4-36x^3+40x^2+8x-10$