Answer to Question #338424 in Algebra for Kaygee

Question #338424

Tn=5n-4

Expert's answer

"T_n=5n-4=1+5(n-1)"

Arithmetic progression: "T_1=1, d=5."

"S_n=\\dfrac{1+5n-4}{2}\\cdot n=\\dfrac{5n^2-3n}{2}"

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