"h(t)=-16t^2+56t+32"
"h'(t)=-32t+56=0"
"t=56\/32=1.75"
"h''(t)=-32<0"
So it is maximum
"h(t)=-16(1.75^2)+56(1.75)+32=81"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment