Solve this system of equations.
(x + 1)2 + (y + 1)2 = 25,x + y = 5
Solution
From second equation y = 5 – x
Let’s substitute this into first equation:
(x + 1)2 + (6 – x)2 = 25 => 2x2 – 10x + 37 = 25 => x2 – 5x + 6 = 0 => x1 = 2, x2 = 3
Substituting these into second equation y1 = 3, y2 = 2
So there are two solutions of the given system of equations:
x1 = 2, y1 = 3 and x2 = 3, y2 = 2
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