Find the centroid of the triangle whose vertices are (−1,0), (1,0), 𝑎𝑛𝑑 (0,3
We know that the centroid of the triangle "(\\frac{x_1+x_2+x_3}{3};\\frac{y_1+y_2+y_3}{3})"
Where "(x_1;y_1);(x_2;y_2);(x_3;y_3)" are the vertices of the
triangle SO, centroid= "(\\frac{(-1)+1+0}{3};\\frac{0+0+3}{3})=(\\frac{0}{3};\\frac{3}{3})=(0;1)"
Hence, this is the answer.
Comments
Leave a comment