∫4 sin 8t cos 3t dt
Solution
∫4 sin 8t cos 3t dt = 2∫2 sin 8t cos 3t dt = 2∫(sin(8t+3t) + sin(8t-3t)) dt = 2∫(sin11t + sin 5t) dt = 2( ∫sin11t dt + ∫ sin 5t dt ) = – (2/11) cos11t – (2/5) cos5t+c.
Answer
∫4 sin 8t cos 3t dt = – (2/11) cos11t – (2/5) cos5t +c.
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