"Solve \t\u222b\u2592\u221bx dx"
"\\int {\\sqrt[3]{x}} dx = \\int {{x^{\\frac{1}{3}}}} dx = \\frac{{{x^{\\frac{1}{3} + 1}}}}{{\\frac{1}{3} + 1}} + C = \\frac{{{x^{\\frac{4}{3}}}}}{{\\frac{4}{3}}} + C = \\frac{3}{4}x\\sqrt[3]{x} + C"
Answer: "\\frac{3}{4}x\\sqrt[3]{x} + C"
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