Since the function is bijective, we know that it is injective and surjective.
Thus define a function;
f:N→N, defined by f(x)={x−1x+1if x is evenif x is odd
The above function is bijective.
Thus, we have a=1∈N in both cases and b={−11∈Nif x is evenif x is odd
Hence, for this function with a,b∈N we have a+b=2
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