Answer to Question #33900 in Combinatorics | Number Theory for eka

Question #33900

Find the smallest integer a>5 such that 4|a, 6|(a+1), 7| (a+2) and 8|(a+1)

Expert's answer

This system has no solution, because if 4|a then a is even and a+1 is odd. But the odd number isn't divided by 6 without remainder.

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