42. Prove that there exists an increasing infinite sequence of triangular
numbers (i.e. numbers of the form tn = -1/2 n(n+ 1), n = 1, 2, ... ) such that
every two of them are relatively prime.
We show first that if for some positive integer m we have m triangular
numbers "a_1 < a_2 < \\dots < a_m" which are pairwise relatively prime, then there
exists a triangular number "t>a_m" such that "(t, a_1, a_2,\\dots , a_m) = 1".
In fact, let "a = a_1 a_2 \\cdots a_m"; the numbers "a+ 1" and "2a+ 1" are relatively prime to "a". The number
"a_{m+1}=t_{2a+1}=\\frac{(2a+1)(2a+2)}{2}=(a+1)(2a+1)"
is triangular number ">a_m" being relatively prime to a, it is relatively prime
to every number "a_1,a_2,\\dots,a_m".
It follows that if we have a finite increasing sequence of pairwise relatively prime triangular numbers, then we can always find a triangular number exceeding all of them and pairwise relatively prime to them. Taking always the least such number we form the infinite sequence
"t_1=1, t_2=3, t_4=10, t_{13}=91, t_{22}=253,\\dots"
of pairwise relatively prime triangular numbers.
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