Write Z = 4√(3) e(7π/4)i in algebraic form
"z = 4\\sqrt 3 {e^{\\frac{{7\\pi }}{4}i}} = 4\\sqrt 3 (\\cos \\frac{{7\\pi }}{4} + i\\sin \\frac{{7\\pi }}{4}) = 4\\sqrt 3 \\left( {\\frac{1}{{\\sqrt 2 }} - \\frac{1}{{\\sqrt 2 }}i} \\right) = 2\\sqrt 2 \\cdot \\sqrt 3 - 2\\sqrt 2 \\cdot \\sqrt 3 i = 2\\sqrt 6 - 2\\sqrt 6 i"
Answer: "2\\sqrt 6 - 2\\sqrt 6 i"
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