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Dear Tota. Using provided reasonings in the solution, you can prove
your statement, because it holds for positive real numbers and for
absolute value of purely imagine numbers (Ai, where A is real), taking
into account that any complex number can be represented as the sum of
real and purely imagine number, square root of a sum is less than the
sum of absolute value of each term.
Assignment Expert
29.12.14, 18:43
Dear vallle. Thank you for adding information.
vallle
29.12.14, 17:27
you are right , i missed word { absolutely} convergent for the first
series Zn then Zn^2 is convergent . Sorry
Tota
29.12.14, 17:19
Sorry Sorry , I missed one word { Absolutely } before convergent of Zn
in the first Series should Absolutely convergent Really appreciate
your reply
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Dear Tota. Using provided reasonings in the solution, you can prove your statement, because it holds for positive real numbers and for absolute value of purely imagine numbers (Ai, where A is real), taking into account that any complex number can be represented as the sum of real and purely imagine number, square root of a sum is less than the sum of absolute value of each term.
Dear vallle. Thank you for adding information.
you are right , i missed word { absolutely} convergent for the first series Zn then Zn^2 is convergent . Sorry
Sorry Sorry , I missed one word { Absolutely } before convergent of Zn in the first Series should Absolutely convergent Really appreciate your reply
Leave a comment