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Answer to Question #210059 in Differential Equations for Faith
Question #210059
Solve the following differential equation subject to the given initial conditions.
1.dy/d0=ysin0;y(π)=3.
2.x²dy/d0=y-xy;y(1)=1.
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Comments
Thank you for correcting us.
On the first question Integral of sin0 is -cos0 not cos0
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