Find a partial differential equation by eliminating a and b from the equations
z^2 = ax^3 + by^3 + ab.
Let us find a partial differential equation by eliminating "a" and "b" from the equations "z^2 = ax^3 + by^3 + ab."
Let us use the implicit differentiation.
It follows that
"2zz_x = 3ax^2" and "2zz_y = 3by^2."
Therefore, "a=\\frac{2zz_x}{ 3x^2}" and "b=\\frac{2zz_y}{ 3y^2}."
We conclude that the partial differential equation is of the form:
"z^2 = \\frac{2zz_x}{ 3x^2}x^3 + \\frac{2zz_y}{ 3y^2}y^3 + \\frac{2zz_x}{ 3x^2}\\frac{2zz_y}{ 3y^2}."
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