Solve π§π = βπ₯.
"\ud835\udc67\ud835\udc5d = \u2212\ud835\udc65"
"p=\\frac{dz}{dx}"
"\ud835\udc67\\frac{dz}{dx} = \u2212\ud835\udc65"
"zdz=-xdx"
"\\frac{z^2}{2}=-\\frac{x^2}{2}+\\frac C2"
"z^2+x^2=C"
Answer: "z^2+x^2=C" .
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