Assume the total cost of a tertiary education will be R75 000 when your child enters university in 18 years. You presently have R7 000 to invest. What rate of interest must you earn on your investment to cover the cost of your child’s tertiary education?
Amount Invested = R 7000
Total Cost of Tertiary Education = R75,000
Time Period = 18 years
Compound Interest Formula
"A = P{\\left( {1 + \\frac{r}{n}} \\right)^{nt}}"
Here
"A" – Final amount which in this case is "R 75,000"
"P" – Initial amount invested which in this case is "R 7,000"
"r" – Annual interest rate (required to find)
"n" – Compounding period per year, which in this case is "1"
"t" – The number of time periods
Using the values, we get
"75000 = 7000{\\left( {1 + \\frac{r}{1}} \\right)^{\\left( 1 \\right)\\left( {18} \\right)}}"
"{\\left( {1 + r} \\right)^{18}} = \\frac{{75000}}{{7000}}\\\\"
"r = {\\left( {\\frac{{75000}}{{7000}}} \\right)^{\\left( {1\/18} \\right)}} - 1\\\\"
"r = 0.1408280192"
Hence the annual interest rate must be 14.08 %
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