Q2. Find the distance of 𝑃(−3,2) from the line with equation 5𝑥 + 12𝑦 + 11 = 0.
The given point is 𝑃(−3,2)
Equation of line is 5𝑥 + 12𝑦 + 11 = 0.
We know that the distance between point and line is
"d=\\frac{|5\ud835\udc65 + 12\ud835\udc66 + 11|}{\\sqrt{5^2+12^2}}"
Now, substituting the values,
"\\Rightarrow d = \\frac{|5\\times (-3)+12\\times2+11|}{\\sqrt{25+144}}"
"\\Rightarrow d = \\frac{|-15+24+11|}{\\sqrt{169}}"
"\\Rightarrow d = \\frac{20}{13}"
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