Answer to Question #248530 in Geometry for HASSI

Question

A circle has an area equal to 25pi cm². Its diameter AB coincides with one of the sides of triangle ACB whose vertex C lies on the circle. If the triangle has an area equal to 11 cm², find the perimeter of the triangle.

Answer 1

area of circle=$\pi r^2=25\pi$

$r^2=25,r=5$

diameter AB=$2\times5=10cm$

area of triangle$=1/2bh=1/2\times10\times h=11$

$5h=11,h=2.2cm$

hypotenuse=$\sqrt{2.2^2+5^2}=5.463$

perimeter of triangle=$10+5.463\times2=20.926cm$