Suppose T€L(R^2) is defined by T(x, y) =(-3y,x).find the eigenvalues of T
Answer:-
Let "\\lambda" be an eigenvalues of T such that "T(x,y)=\u03bb(x,y)" .
Then we have "T(x,y)=\u03bb(x,y)" so "(\u22123y,x)=(\u03bbx,\u03bby)" , thus "\u03bbx=\u22123y" and "x=\u03bby" . So we have "\u03bb(\u03bby)=\u22123y"
implies we have "\\lambda^2 = -3" . which has no solution. So there arent any eigenvalues.
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