Express the polynomial 1+3x+4x2 as a linear combination of the polynomials
1+2x+3x2, -1+x+x2 and 2+x+x2
1+3x+4x2= a(1+2x+3x2) + b(-1+x+x2) + c(2+x+x2) = (a-b+2c) + (2a+b+c)x + (3a+b+c)x2
"\\begin{cases}\n a-b+2c = 1 \\\\\n 2a+b+c = 3 \\\\\n 3a+b + c = 4\n\\end{cases}"
subtraction the second equation from the third gives: a =1
addition the first equation and the secong gives 3a + 3c = 4, and from this c = 1/3
from the fist equation: b = a +2c - 1= 2/3
so 1+3x+4x2= (1+2x+3x2) + 2/3 (-1+x+x2) + 1/3 (2+x+x2)
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