Solve the following pair of linear equation by matrix method 2p +q =5
5p +3=11
The coefficient matrix is:
The variable matrix is:
The constant matrix is:
Thus, to solve a system "AX=B," for "X," multiply both sides by the inverse of "A"
and we shall obtain the solution:
Provided the inverse "A^{-1}" exists, this formula will solve the system.
The inverse "A^{-1}" exists.
"X=A^{-1}B=\\begin{pmatrix}\n 0 & 1\/5 \\\\\n 1 & -2\/5\n\\end{pmatrix}\\begin{pmatrix}\n 5 \\\\\n 8\n\\end{pmatrix}"
"=\\begin{pmatrix}\n 0(5)+(1\/5)(8) \\\\\n 1(5)+(-2\/5)(8)\n\\end{pmatrix}=\\begin{pmatrix}\n 8\/5 \\\\\n 9\/5\n\\end{pmatrix}"
"\\begin{pmatrix}\n p \\\\\n q\n\\end{pmatrix}=\\begin{pmatrix}\n 8\/5 \\\\\n 9\/5\n\\end{pmatrix}"
"p=8\/5, q=9\/5"
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