Show that T(x1, x2, x3, x4) = 3x1_7x2+5x4 is a linear transformation by finding the matrix for the transformation. Then find the basis for the null space of the transformation.
Solutiob;
The linear transformation;
"T\\begin{bmatrix}\n x_1 \\\\\n x_2\\\\\nx_3\\\\\nx_4\n\\end{bmatrix}" ="\\begin{bmatrix}\n 3 & -7&0&5 \\\\\n \n\\end{bmatrix}"
The Null space of the transform is the solution of the homogeneous system Ax=0;
Where A is the matrix;
"\\begin{bmatrix}\n 3 &-7&0&5\\\\\n\\end{bmatrix}"
"3x_1-7x_2+5x_4=0"
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