How is w=(3,5,1)∈R
3
a linear combination of u=(0,−2,2)
and v=(1,3,−1)
?
w is a linear combination of u and v if exist such x and y so x*u +y*v = w
That means that "\\begin{bmatrix}\n 0 & 1 \\\\\n -2 & 3 \\\\\n 2 & -1\n\\end{bmatrix} \\cdot\n\\begin{bmatrix}\n x \\\\\n y \\\\\n\\end{bmatrix} =\n\\begin{bmatrix}\n 3 \\\\\n 5 \\\\\n 1\n\\end{bmatrix}"
Or "\\begin{cases}\n y = 3 \\\\\n -2 x + 3y = 5 \\\\\n 2x - y = 1\n\\end{cases}"
From the fist equation find that y = 3, and substitute it in the last equation get 2x -3 = 1, or x = 2. After substituting x=2 and y=3 in the second equation confirmed it is satisfied.
So w = 2*u + 3*v
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