A company owns two flour mills (A and B) which have different production capacities for HIGH, MEDIUM and LOW grade flour. This company has entered contract supply flour to a firm every week with 12, 8, and 24 quintals of HIGH, MEDIUM and LOW grade respectively. It costs the Co. $1000 and $800 per day to run mill A and mill B respectively.
On a day, mill A produces 6, 2, and 4 quintals of HIGH, MEDIUM and LOW grade flour respectively. Mill B produces 2, 2 and 12 quintals of HIGH, MEDIUM and LOW grade flour respectively.
Required tasks:
•Formulate the LP model; how many days per week should each mill be operated in order to meet the contract order most economically standardize? Interpret the result; determine the surplus amount; determine the optimal value using simplex method.
Minimize: "1000x_1+800x_2"
Subject to: "6x_1+2x_2\\geq8"
"2x_1+4x_2\\geq12"
"4x_1+12x_2\\geq24"
"x_1\\geq0, x_2\\geq0"
Convert the minimization problem into its dual. Transposing matrix of coefficients:
Maximize: "8y_1+12y_2+24y_3"
Object to:
"6y_1+2y_2+4y_3\\leq1000"
"2y_1+4y_2+12y_3\\leq800"
"y_1\\geq0, y_2\\geq0, y_3\\geq0"
1st iteration:
"Z_{min}=-24" for "y_3" - pivot column
"b_i\/s_i" in pivot column is minimal for "s_2" ("800\/12<1000\/4" ), so, pivot row is row of "s_2"
Pivot value is intersection of pivot column and pivot row.
Pivot value"=12"
Update table. The new coefficients of the tableau are calculated as follows:
In the pivot row each new value is calculated as: New value = Previous value / Pivot
In the other rows each new value is calculated as:
New value = Previous value - (Previous value in pivot column * New value in pivot row)
2nd iteration:
The pivot column is column of "y_1" , the pivot row is row of "s_1" , pivot value is "16\/3"
3rd iteration:
The pivot column is column of "y_2" , the pivot row is row of "s_2" , pivot value is "5\/16"
4th iteration:
Solution: "x_1=2\/5,x_2=14\/5, Z_{min}=2640"
The minimal cost per day of running mills is $2640. The company operates mills A and B for 0.4 days and 2.8 days per week respectively.
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