Answer to Question #160194 in Operations Research for KALEAB

Question #160194

A company owns two flour mills (A and B) which have different production capacities for HIGH, MEDIUM and LOW grade flour. This company has entered contract supply flour to a firm every week with 12, 8, and 24 quintals of HIGH, MEDIUM and LOW grade respectively. It costs the Co. $1000 and $800 per day to run mill A and mill B respectively. 

On a day, mill A produces 6, 2, and 4 quintals of HIGH, MEDIUM and LOW grade flour respectively. Mill B produces 2, 2 and 12 quintals of HIGH, MEDIUM and LOW grade flour respectively.

Required tasks:

•Formulate the LP model; how many days per week should each mill be operated in order to meet the contract order most economically standardize? Interpret the result; determine the surplus amount; determine the optimal value using simplex method. 



1
Expert's answer
2021-02-02T05:47:28-0500

Minimize: "1000x_1+800x_2"

Subject to: "6x_1+2x_2\\geq8"

"2x_1+4x_2\\geq12"

"4x_1+12x_2\\geq24"

"x_1\\geq0, x_2\\geq0"

Convert the minimization problem into its dual. Transposing matrix of coefficients:

Maximize: "8y_1+12y_2+24y_3"

Object to:

"6y_1+2y_2+4y_3\\leq1000"

"2y_1+4y_2+12y_3\\leq800"

"y_1\\geq0, y_2\\geq0, y_3\\geq0"


1st iteration:


"Z_{min}=-24" for "y_3" - pivot column

"b_i\/s_i" in pivot column is minimal for "s_2" ("800\/12<1000\/4" ), so, pivot row is row of "s_2"

Pivot value is intersection of pivot column and pivot row.

Pivot value"=12"


Update table. The new coefficients of the tableau are calculated as follows:

In the pivot row each new value is calculated as: New value = Previous value / Pivot

In the other rows each new value is calculated as:

New value = Previous value - (Previous value in pivot column * New value in pivot row)


2nd iteration:



The pivot column is column of "y_1" , the pivot row is row of "s_1" , pivot value is "16\/3"


3rd iteration:



The pivot column is column of "y_2" , the pivot row is row of "s_2" , pivot value is "5\/16"


4th iteration:



Solution: "x_1=2\/5,x_2=14\/5, Z_{min}=2640"

The minimal cost per day of running mills is $2640. The company operates mills A and B for 0.4 days and 2.8 days per week respectively.


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