b) The table below shows a transportation problem. Solve it using the Vogel approximation
method.
Destinations
Sources 1 2 3 4 Supply
A 2 2 12 21 80
B 4 3 13 7 60
C 5 12 1 6 60
Demand 50 60 30 40
c) State five objectives of inventory management.
d) The following table shows a pay-off matrix for a game. Use it to solve the game.
e) State four characteristics of 2-persons zero sum game.
f) A company’s ordering cost is sh 25 and the holding cost is 10% of average inventory.
Given that the total cost is shs. 750, find the demand.
g) State the two categories of inventory models.
b)
Here Total Demand = 180 is less than Total Supply = 200. So We add a dummy demand constraint with 0 unit cost and with allocation 20.
Now, The modified table is
The maximum penalty, 11, occurs in column D3.
The minimum cij in this column is c33=1.
The maximum allocation in this cell is min(60,30) = 30.
It satisfy demand of D3 and adjust the supply of S3 from 60 to 30 (60 - 30=30).
The maximum penalty, 5, occurs in row S3.
The minimum cij in this row is c35=0.
The maximum allocation in this cell is min(30,20) = 20.
It satisfy demand of Ddummy and adjust the supply of S3 from 30 to 10 (30 - 20=10).
c)
d)
Select minimum from the maximum of columns
Column MiniMax = (6)
Select maximum from the minimum of rows
Row MaxiMin = [2]
Here, Column MiniMax ≠ Row MaxiMin
∴ This game has no saddle point.
"P_{Adj}=\\begin{bmatrix}\n 2 & -7 \\\\\n -6 & 1\n\\end{bmatrix}"
"P_{Cof}=\\begin{bmatrix}\n 2 & -6 \\\\\n -7 & 1\n\\end{bmatrix}"
Player A's optimal strategies = "\\frac{\\begin{bmatrix}\n 1 & 1 \\\\\n \n\\end{bmatrix}\\times P_{Adj}}{\\begin{bmatrix}\n 1 & 1 \\\\\n \n\\end{bmatrix}\\times P_{Adj}\\times \\begin{bmatrix}\n 1 \\\\\n 1\n\\end{bmatrix}}=\\begin{bmatrix}\n 2\/5 & 3\/5 \\\\\n \n\\end{bmatrix}"
p1=2/5 and p2=3/5, where p1 and p2 represent the probabilities of player A's, using his strategies A1 and A2 respectively.
Player B's optimal strategies = "\\frac{\\begin{bmatrix}\n 1 & 1 \\\\\n \n\\end{bmatrix}\\times P_{Cof}}{\\begin{bmatrix}\n 1 & 1 \\\\\n \n\\end{bmatrix}\\times P_{Adj}\\times \\begin{bmatrix}\n 1 \\\\\n 1\n\\end{bmatrix}}=\\begin{bmatrix}\n 1\/2 & 1\/2 \\\\\n \n\\end{bmatrix}"
q1=1/2 and q2=1/2, where q1 and q2 represent the probabilities of player A's, using his strategies B1 and B2 respectively.
Hence, Value of the game V = (Player A's optimal strategies) × (Payoff matrix Pij) × (Player B's optimal strategies):
"V=\\begin{bmatrix}\n 2\/5 & 3\/5 \\\\\n \n\\end{bmatrix}\\begin{bmatrix}\n 1& 7 \\\\\n 6 & 2\n\\end{bmatrix} \\begin{bmatrix}\n 1\/2 \\\\\n 1\/2\n\\end{bmatrix}=4"
e)
f)
Total cost = holding cost + ordering cost
holding cost = "750-25=725" = 10% x average inventory
average inventory = "725\/0.1=7250"
Demand = average inventory/ordering cost
Demand = "7250\/25=290"
g)
Fixed Reorder Quantity System:
the maximum and minimum of standard inventory quantity are defined in advance, and the quantity of inventory gradually decreases, and when the number reaches ROP (Reorder Point), an order of EOQ (Economic Order Quantity) is placed.
Fixed Reorder Period System:
an inventory control method where orders are periodically placed, but the order quantity is different every time.
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