Let a∈ R be an irrational number.
Then a"\\notin" Q (rationals)
Let us suppose the sets :
P = (- ∞ , a ) ∩ Q
T = ( a, ∞ ) ∩ Q
Let x ∈P
Let B(∈ ,x) be an open ball in of x in Q
Then, for all x in P, there exists ∈ from R such that B(∈ ,x) lies in P if
∈=a−x
Similarly, for all x in T , there exists ∈ from R such that B (∈ , x ) lies in T if
∈=x−a
So , there open neighborhoods of P and T in Q, hence P and T are open sets in Q.
Now,
P ∪ T = Q , P∩ T = ∅ where P and T are non-empty open sets.
So, P and T are a separation in Q.
Hence, the result.
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