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Solve the following linear system Ax = b of equations with partial pivoting



x-y+3z=3



2x+y+4z=7



3x+5y-2z=6



Store the multipliers and also write the pivoting vectors.

1) If ((xn,yn)) is a bounded sequence, then


((xn,yn)) has convergent subsequence.



2)((xn,yn)) is Cauchy if and only if ((xn,yn)) is convergent.

((xn,yn)) is convergent if and only if ((xn,yn)) is bounded and every convergent subsequence of ((xn,yn)) has the same limit.

((xn,yn)) is convergent if and only if ((xn,yn)) is bounded.

((xn,yn)) is said to be Cauchy if and only if both (xn) and (yn) are Cauchy sequences in R.

A function f(x) is defined for the range -2a<=x<=2a by







f(x){2a-x if -2a<=x<0







f(x){2a+x if 0<x<=2a







Sketch f(x) and state the domain and range of f(x)

13. Let b in mathbb F satisfy 0 < b < 1.





lim (n * b ^ n) = 0 [Hint: Use the Binomial Theorem

Let ((Xn, Yn)) and ((Un, Vn)) be sequences in R2, and let


(X0, Y0), (U0, Vo) belong to R2.


(i) If (Xn,Yn) converges to (X0, Y0) and (Un, Vn) converges to (Uo, Vo), then (Xn,Yn)+(Un, Vn) converges to (X0,Y0) + (U0,V0) and (Xn,Yn).(Un,Vn) converges to (Xo,Y0)(Uo, V0).



ii) If (Xn, Yn) converges to (X0, Y0), then for any r belonging to R, r(Xn,Yn) converges to r(X0,Y0).



((xn,yn) is convergent iff both (xn}) and (yn) are convergent. In fact, for(x0 ,y0) in R2, we have (xn ,yn) converging to (x0,y0) iff xn converges to x0 and yn converges to y0

Given a sequence ((xn,yn)) is R2 .prove that if ((xn,yn)) is bounded ,then (xn) and (yn) are bounded.

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