If P (A|B) = 0.5, P (A) = 0.45 and P (B) = ?
Bayes' theorem:
"P(A|B)=\\frac{P(B|A)P(A)}{P(B)}"
then:
"P(B)=\\frac{P(B|A)P(A)}{P(A|B)}=\\frac{0.45P(B|A)}{0.5}=0.9P(B|A)"
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