Give an example of a nowhere dense set in a metric space .substantiate your claim
Solution:
Let X be a metric space. A subset A ⊆ X is called nowhere dense in X if the interior of the closure of A is empty, i.e. (A)◦ = ∅. Otherwise put, A is nowhere dense iff it is contained in a closed set with empty interior.
For example, "\\mathbb{Z}" is nowhere dense in "\\mathbb{R}" because it is its own closure, and it does not contain any open intervals (i.e. there is no (a, b) s.t. "(a, b) \\subset \\overline{\\mathbb{Z}}=\\mathbb{Z}" . An example of a set which is not dense, but which fails to be nowhere dense would be "\\{x \\in \\mathbb{Q} \\mid 0<x<1\\}" . Its closure is [0,1], which contains the open interval (0,1). Using the alternate definition, you can note that the set is dense in "(0,1) \\subset \\mathbb{R}" .
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