Let the two equal angles be at vertex "A" and "B", and the third angle be at vertex "C". Now, we draw a line segment from "C" to the midpoint of "\\overline{AB}" which we call "M".
Then we have two triangles "\\triangle{AMC}" and "\\triangle{BMC}", which are congruent by the SAS rule.
Since "\\overline{AC}" and "\\overline{BC}" are equal
"\\therefore" two sides of the spherical triangle "\\triangle {ABC}" are equal making it an isosceles spherical triangle
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