Answer to Question #341801 in Trigonometry for Fox

Question #341801

Solve the triangle.

A = 21°, C = 105 °, c = 5

Expert's answer

B=180⁰-105⁰-21⁰=54⁰

a/sinA=b/sinB=c/sinC

a/sin21⁰=b/sin54⁰=5/sin105⁰

a=5sin21⁰/sin105⁰=5*0.3589/0.9659=1.85

b=5sin54⁰/sin105⁰=5*0.809/0.9659=4.18

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