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Answer to Question #62146 in Trigonometry for Glenn
Question #62146
If x=a*sinQ + b*cosQ and y=a*cosQ + b*sinQ
Prove that (x^2+y^2)(a^+y^2) - 4abxy = (a^2 - b^2)^2
Prove that (x^2+y^2)(a^+y^2) - 4abxy = (a^2 - b^2)^2
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