Answer to Question #74960 in Trigonometry for Anonymous
Given tanu=-1/3 and sin〖u<0,〗 find sin(u/2). (Assume 0≤u<2π.)
-√((10+3√10)/20) b. √((10-3√10)/20) c. √((10+3√10)/20)
d. -√((10-3√10)/20) e. None of these
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2018-03-26T10:03:07-0400
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