Answer to Question #164568 in Atomic and Nuclear Physics for Magnificent

Question

An RLC circuit is connected to 60hz, 240volts a.c supply. If R=50ohms, C=100uf and M=0.12h. Calculate the power used in circuit

Answer 1

$$P=\frac{U^2}{Z}\\P=\frac{U^2}{\sqrt{R^2+(2\pi f L-\frac{1}{2\pi f C})^2}} \\P=\frac{240^2}{\sqrt{50^2+(2\pi (60)(0.12)-\frac{1}{2\pi (60)(10^{-4})})^2}}=1079\ W$$