Answer to Question #235250 in Atomic and Nuclear Physics for Vishakha

Question

Find the mean square radius of 56Ni nucleus assuming it to be a spherical nucleus with sharp boundary

Answer 1

Given:

$A=56$

$r_0=1.3*10^{-15}\:\rm m$

The radius of nucleus

$$R=r_0A^{1/3}$$

$$R=1.3*10^{-15}{\:\rm m}*56^{1/3}=5.0*10^{-15}{\:\rm m}\\=5.0\:\rm fm$$