Answer to Question #216080 in Classical Mechanics for tonny419

Question

Two crossed belts on pulleys of diameters 3.6 m and 2.4 m connect two parallel shafts with centres 4.2 meters apart. The maximum tension in the belts is limited to 1200 N and friction between the belts and the pulley, μ = 0.26. The smaller pulley has a speed of 300 rev/min.

2.1. Find the power that can be transmitted. (8)

2.2. What would be transmitted if open belts were used. (8)

Answer 1

1)

$P_1=\mu F l\nu\frac {d_2}{d_1}=9.8~kW,$

2)

$P_2=P_1\frac{d_1^2}{d_2^2}=4.4~kW.$