Answer to Question #235791 in Classical Mechanics for Sridhar

Question

The position of a particle moving along X axis varies with time as X=10-2t

Answer 1

Given that ;

$x=10t-2t^2$

So;$V=\frac {dx} {dt} =10-4t$

The particle will come to rest if v = 0

$10-4t=0$

$t=2.5s$