What force parallel to the inclined is required to push a 40 kg up on a 50o inclined plane if the coefficient of friction (static) is 0.3.
"\\vec F+m\\vec g+\\vec N+\\vec{F_{fr}}=\\vec 0,"
"Ox:F-F_{fr}-mg\\sin\\alpha=0,"
"Oy:N=mg\\cos\\alpha,"
"F_{fr}=\\mu N,"
"F=mg(\\mu\\cos\\alpha+\\sin \\alpha)=376~N."
Comments
Leave a comment