Write down the conditions for maxima and determine the angle:
"d\\sin\\theta_1=m\\lambda_1,\\\\\nd\\sin\\theta_2=m\\lambda_2.\\\\\\space\\\\\n\\theta_1=\\arcsin\\frac{m\\lambda_1}{d},\\\\\\space\\\\\n\\theta_2=\\arcsin\\frac{m\\lambda_2}{d}." For the length between the grating and screen 2.0 m, find the change in linear separation:
"\\Delta z(m)=D(\\tan\\theta_2-\\tan\\theta_1)=\\\\\\space\\\\\n=D(\\tan\\arcsin\\frac{m\\lambda_2}{d}-\\tan\\arcsin\\frac{m\\lambda_1}{d})=\\\\\\space\\\\\n=2[\\tan\\arcsin(0.26m)-\\tan\\arcsin(0.25m)]."
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