A 400kg mass on a 30 degree inclined plane is acted upon by a force equal to 4800N at an angle 30 degree with the incline as shown in the figure below.
a)
"m\\vec a=\\vec F+m\\vec g,"
"a=\\frac Fm\\cos 30\u00b0-g\\sin 30\u00b0=5.5~\\frac m{s^2},"
b)
"m\\vec a=\\vec F+m\\vec g+\\vec F_{fr},"
"a=\\frac Fm\\cos 30\u00b0-g\\sin 30\u00b0-\\mu g\\cos 30\u00b0=3.8~\\frac m{s^2}."
Comments
Thanks a lot for your clear answer.
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