If a clock expends 2 W of power from a 1.5 V battery, what amount of current is supplying the clock? Ans: 1.3 A
Gives
P=2W
V=1.5 V
We know that
"P=IV \\\\I=\\frac{P}{V}"
Put value
"I=\\frac{2}{1.5}=1.3Amp"
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