Four resistors when connected in series give an equivalent
resistance if 75.0 Ω. Three of the resistors have values 18.0 Ω, 6.0 Ω, and
24.0 Ω, respectively. What is the resistance of the fourth resistor?
Answer
So the fourth resistance is
"R_4=R-R_1-R_2-R_3\\\\=75-(18+6+24) \\\\=27\\Omega"
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