A 12-V battery, a 12-ohm resistor and a 4-ohm resistor are connected as
shown. The current in the 12-ohm resistor is ____ that in the 4-ohm resistor.
Answer
Now think these resistance are connected in series then
Total resistance
R=12+4=16"\\Omega"
So current is same in both resistance so
"I =\\frac{V}{R}\\\\=\\frac{12}{16}\\\\=0.75A"
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