Answer to Question #338878 in Electric Circuits for Austyn

Question

A proton accelerates from rest in a uniform electric field of 5NC^-1. At some time later it's speed is 1.2×10^6 ms^-1. What is the acceleration of the proton

Answer 1

$$a=\frac{F}{m}=\frac{qE}{m}$$

$$a=\frac{1.6*10^{-19}*5}{9.1*10^{-31}}=8.8*10^{11}\:\rm m/s^2$$