Answer to Question #346353 in Electric Circuits for Nuel Fudalan

Question

A 100-m-long copper wire of radius 0.12 mm is connected across a 1.5-V battery has 9.4 x 10¹⁹ electrons passing a cross section of the wire every 3.0 s. Calculate the resistance of this wire.

Answer 1

$$I=\frac{q}{t}=\frac{9.4*10^{19}*1.6*10^{-19}}{3.0}=5.0\:\rm A$$

$$R=\frac{V}{I}=\frac{1.5}{5.0}=0.3\:\Omega$$