A toroid core has N = 1200 turns, length L = 80cm, cross-sectional area A = 60cm2
,
current I = 1.5A. Compute B and H. Assume an empty core.
Answer
Magnetic field due to toroid
"B=\\frac{\\mu_0Ni}{2\\pi r}\\\\=\\frac{2*10^{-7}*1.5}{0.044}\\\\=68.64*10^{-7}T"
Now H
"H=\\frac{B}{\\mu_0}\\\\=\\frac{68.64*10^{-7}}{4*3.14*10^{-7}}\\\\=5.47T"
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