Answer to Question #320051 in Electricity and Magnetism for Krisha

Question #320051

A point charge q₁= +3.90 is at origin. How far should the second point charge of +6.30 be placed to have electric potential energy of 0.700 J?

Expert's answer

Answer

The distance must

"R=\\frac{Kqq'}{U}\\\\=\\frac{9*10^9*3.9*6.30}{0.7}\\\\=315.9m"

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