A square cost of resistance 4ohm ,50 turns and side length 5cm is places with it's plane making on amgle of 40° with a uniform field 2T.In 4.5 s the coil rotates until it's plane becomes parallel to the.magnetic field.Find the current induced in the coil.
The current induced in the coil
"I=\\frac{V}{R}=\\frac{\\Delta \\Phi}{R\\Delta t}=\\frac{NBA(1-\\cos\\theta)}{R\\Delta t}""I=\\frac{50*2*0.05^2(1-\\cos40^\\circ)}{4*4.5}=3.25*10^{-3}\\:\\rm A"
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